A) \[\pi {{a}^{2}}\]
B) \[2\pi {{a}^{2}}\]
C) \[3\pi {{a}^{2}}\]
D) \[4\pi {{a}^{2}}\]
Correct Answer: A
Solution :
Since the curve is symmetrical about x-axis, therefore Required area\[A=2\int_{0}^{a}{a\sqrt{\frac{a-x}{x}}\,dx}\] Put \[x=a{{\sin }^{2}}\theta \] \[\Rightarrow dx=2a\sin \theta .\cos \theta \,d\theta \]You need to login to perform this action.
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