A) \[\frac{56}{9}\] sq. unit
B) \[\frac{64}{9}\] sq. unit
C) 8 sq. unit
D) None of these
Correct Answer: D
Solution :
Area \[=\int_{0}^{4}{\sqrt{3x+4}}dx=\left| \frac{{{(3x+4)}^{3/2}}}{3.(3/2)} \right|_{0}^{4}\] \[=\frac{2}{9}\times 56=\frac{112}{9}sq.\]unit.You need to login to perform this action.
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