A) \[\frac{1}{2}\]
B) 1
C) \[-1\]
D) 2
Correct Answer: B
Solution :
\[\int_{\,0}^{\,2}{{{2}^{kx}}dx=\frac{3}{\log 2}\Rightarrow {{2}^{2k}}-1=3k}\]. Now check from options, only satisfies the above condition.You need to login to perform this action.
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