A) \[\frac{16}{3}\]
B) \[\frac{64}{3}\]
C) \[7\sqrt{2}\]
D) None of these
Correct Answer: B
Solution :
Required area = area of OABC ? area of OBC \[=16\times 4-\int_{0}^{16}{\sqrt{x}}dx=64-\left[ \frac{{{x}^{3/2}}}{3/2} \right]_{0}^{16}=\frac{64}{3}.\]You need to login to perform this action.
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