A) \[\frac{16}{3}sq.\,unit\]
B) \[-\frac{16}{3}sq.\,unit\]
C) \[\frac{4}{7}sq.\,unit\]
D) Cannot be calculated
Correct Answer: A
Solution :
\[\int_{0}^{2}{({{x}^{2}}-4x)dx=\left[ \frac{{{x}^{3}}}{3}-\frac{4{{x}^{2}}}{2} \right]_{0}^{2}=\frac{16}{3}sq.}\]unit.You need to login to perform this action.
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