A) 125/6
B) 125/3
C) 125/2
D) None of these
Correct Answer: A
Solution :
Solving \[y=0\] and \[y=4+3x-{{x}^{2}},\]we get \[x=-1,\,4\]. Curve does not intersect x-axis between \[x=-1\]and \[x=4\]. \ Area \[=\int_{-1}^{4}{(4+3x-{{x}^{2}})dx=\frac{125}{6}}\].You need to login to perform this action.
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