A) \[\frac{2}{3}{{a}^{2}}\]sq. unit
B) \[\frac{4}{3}{{a}^{2}}\]sq. unit
C) \[\frac{8}{3}{{a}^{2}}\]sq. unit
D) \[\frac{3}{8}{{a}^{2}}\]sq. unit
Correct Answer: C
Solution :
Area = \[2\int_{0}^{a}{\,\,y\,dx=2\int_{0}^{a}{\sqrt{4ax}}\,\,dx}\] \[2\times 2\sqrt{a}\times \frac{2}{3}\left| {{x}^{3/2}} \right|_{0}^{a}=\frac{8}{3}{{a}^{2}}\] sq. unit.You need to login to perform this action.
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