A) \[e+\frac{1}{e}\]
B) \[e-3\]
C) \[e+\frac{1}{e}-2\]
D) \[e+\frac{1}{e}+2\]
Correct Answer: C
Solution :
Given equations of curves \[y={{e}^{x}};y={{e}^{-x}}\] and straight line \[x=1\] We know that area of the figure bounded by the curves and straight line \[=\int_{0}^{1}{({{e}^{x}}-{{e}^{-x}})dx=[{{e}^{x}}+{{e}^{-x}}]\,_{0}^{1}\,=\,e+\frac{1}{e}-2.}\]You need to login to perform this action.
You will be redirected in
3 sec