A) 4
B) 2
C) 3
D) 1
Correct Answer: D
Solution :
Required area \[=\int_{1}^{3}{|x-2|dx}\,\,=\int_{1}^{2}{(2-x)dx+\int_{2}^{3}{(x-2)dx}}\] \[=\left[ 2x-\frac{{{x}^{2}}}{2} \right]_{1}^{2}+\left[ \frac{{{x}^{2}}}{2}-2x \right]_{2}^{3}\]\[=\frac{1}{2}+\frac{1}{2}=1\].You need to login to perform this action.
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