JEE Main & Advanced
Mathematics
Definite Integration
Question Bank
Area Bounded by Region, Volume and Surface Area of Solids of Revolution
question_answer
If A is the area of the region bounded by the curve \[y=\sqrt{3x+4}\], x axis and the line \[x=-1\] and \[x=4\]and B is that area bounded by curve \[{{y}^{2}}=3x+4\], x- axis and the lines \[x=-1\]and \[x=4\] then \[A:B\] is equal to [J& K 2005]
A) \[1:1\]
B) \[2:1\]
C) \[1:2\]
D) None of these
Correct Answer:
A
Solution :
In both cases area will be same, hence ratio \[A:B\] is 1 : 1.