A) 9
B) \[\frac{27}{4}\]
C) 36
D) 18
Correct Answer: A
Solution :
Solving \[{{y}^{2}}=x\]and \[x=2y+3\] \[4{{y}^{2}}={{(x-3)}^{2}}\], \[4x={{x}^{2}}-6x+9\] Þ \[{{x}^{2}}-10x+9=0\]Þ \[(x-1)(x-9)=0\]Þ \[x=1,\,9\]You need to login to perform this action.
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