JEE Main & Advanced Mathematics Definite Integration Question Bank Area Bounded by Region, Volume and Surface Area of Solids of Revolution

  • question_answer If A is the area of the region bounded by the curve \[y=\sqrt{3x+4}\], x axis and the line \[x=-1\] and \[x=4\]and B is that area bounded by curve \[{{y}^{2}}=3x+4\], x- axis and the lines \[x=-1\]and \[x=4\] then \[A:B\] is equal to [J& K 2005]

    A)            \[1:1\]                                     

    B)            \[2:1\]

    C)            \[1:2\]                                     

    D)            None of these

    Correct Answer: A

    Solution :

               In both cases area will be same, hence ratio \[A:B\] is 1 : 1.


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