A) \[\frac{21}{5}\pi \]
B) \[\frac{24}{5}\pi \]
C) \[\frac{2}{15}\pi \]
D) \[\frac{5}{24}\pi \]
Correct Answer: C
Solution :
\[V=\int_{0}^{1}{\pi \,{{x}^{2}}dy}\]\[=\pi \int_{0}^{1}{({{y}^{4}}-{{y}^{2}})dy}\]\[=\pi \,\left[ \frac{{{y}^{5}}}{5}-\frac{{{y}^{3}}}{3} \right]_{0}^{1}\] \[=\pi \,\left[ \frac{1}{5}-\frac{1}{3} \right]\]\[=\frac{-2\pi }{15}\] i.e., \[\frac{2\pi }{15}\], (Volume should be positive).You need to login to perform this action.
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