A) \[1100\sqrt{3}\,c{{m}^{2}}\]
B) \[1323\sqrt{3}\,c{{m}^{2}}\]
C) \[1369\sqrt{3}\,c{{m}^{2}}\]
D) \[1442\sqrt{3}\,c{{m}^{2}}\]
Correct Answer: B
Solution :
(b): Centre of the circle lies on the median. If ?a? is side of equilateral \[\Delta le\], median \[=\frac{a\sqrt{3}}{2}\] In - radius \[=\frac{a\sqrt{3}}{2}\times \frac{1}{3}=\frac{1}{2\sqrt{3}a}a=21\] \[\Rightarrow \]\[a=42\sqrt{3}\] Now find area \[=\frac{\sqrt{3}}{4}{{a}^{2}}\]You need to login to perform this action.
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