A) 3 metre
B) 5 metre
C) 6 metre
D) 2 metre
Correct Answer: A
Solution :
(a): Area of rectangular park \[=60\times 40=2400\]sq. metre Let the width of cross road be\[x\]metre. \[\therefore \] Area of cross roads \[=60x+40x-{{x}^{2}}\] \[=100x-{{x}^{2}}\] According to the question. \[100x-{{x}^{2}}=2400-2109\] \[\Rightarrow \]\[100x-{{x}^{2}}=291\] \[\Rightarrow \]\[{{x}^{2}}-100x+291=0\] \[\Rightarrow \]\[{{x}^{2}}-3x-97x+291=0\] \[\Rightarrow \]\[x\left( x-3 \right)-97\left( x-3 \right)=0\] \[\Rightarrow \]\[\left( x-3 \right)\left( x-97 \right)=0\] \[\Rightarrow \] \[x=3\] because \[x\ne 97\]You need to login to perform this action.
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