A) 9:10
B) 8:9
C) 9:11
D) 11:9
Correct Answer: C
Solution :
(c):- Join AC. In \[\Delta ACD.\text{ }EG\parallel DC\] and E and G are mid-points of AD and AC, respective \[\therefore \]\[EG=\frac{1}{2}DC=\frac{3}{2}\] Similarly, in \[\Delta ABC\] \[GF=\frac{1}{2}AB=1\] \[EF=EG+GF=1+\frac{3}{2}=\frac{5}{2}\] \[\therefore \]Area if trapezium\[=\frac{1}{2}\] (Sum of parallel sides\[\times \]Height) Now, required ratio \[=\frac{Area\,of\,ABFE}{Area\,of\,EFCD}=\frac{\frac{1}{2}\left( 2+\frac{5}{2} \right)\times h}{\frac{1}{2}\left( 3+\frac{5}{2} \right)\times h}=\frac{9}{11}\]You need to login to perform this action.
You will be redirected in
3 sec