A) 160 sq. m
B) \[147\sqrt{3}\]sq. m
C) \[210\sqrt{3}\]sq. m.
D) \[27\sqrt{3}\]sq. nz
Correct Answer: B
Solution :
(b): Let a the side of an equilateral triangle ABC. Area of \[\Delta OBC+area\,of\Delta OAC+area\,of\Delta OAB\]\[=Area\,of\Delta ABC\] \[\frac{1}{2}\times a\times 6+\frac{1}{2}\times a\times 7+\frac{1}{2}\times a\times 8=\frac{\sqrt{3}}{4}{{a}^{2}}\] \[\frac{1}{2}a\times 21=\frac{\sqrt{3}}{4}{{a}^{2}}\] \[a=\frac{42}{\sqrt{3}}=\frac{42\times \sqrt{3}}{3}=14\sqrt{3}\] \[\therefore \] area of triangle \[=\frac{\sqrt{3}}{4}\times {{a}^{2}}\] \[=\frac{\sqrt{3}}{4}{{\left( 14\sqrt{3} \right)}^{2}}=\frac{\sqrt{3}}{4}\times 196\times 3=147\sqrt{3}\] sq.cmYou need to login to perform this action.
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