A) 8 cm and 10 cm
B) 9 cm and 11 cm
C) 10 cm and 12 cm
D) 11 cm and 13 cm
Correct Answer: B
Solution :
(b):- Area of rectangle lies between 40\[c{{m}^{2}}\] and 45\[c{{m}^{2}}\] Now one side = 5 cm Since, area cannot be less than 40\[c{{m}^{2}}\] \[\therefore \]Other side cannot be less than \[=\frac{40}{5}=8\] cm Since, area cannot be greater than 45\[c{{m}^{2}}\] \[\therefore \]Other side cannot be greater than \[=\frac{45}{5}=9\]cm \[\therefore \]Minimum value of diagonal \[=\sqrt{{{8}^{2}}+{{5}^{2}}}\] Maximum value of diagonal \[=\sqrt{{{9}^{2}}+{{5}^{2}}}\] \[=\sqrt{106}=10.3\]cm So, diagonal lies between 9 cm and 11 cm
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