A) \[\frac{1}{2}\]
B) 1
C) 2
D) 4
Correct Answer: C
Solution :
Here, \[\Delta AFE\cong \Delta BDF\cong \Delta CDE\] \[\cong DEF\] \[\therefore \]\[ar(BDEF)\] \[=ar(\Delta \Beta DF)+ar(\Delta DEF)\] \[=2ar(\Delta \Alpha FE)\] \[\Rightarrow \] \[x=2\]You need to login to perform this action.
You will be redirected in
3 sec