A) \[~36\text{ }c{{m}^{2}}\]
B) \[~24\text{ }c{{m}^{2}}\]
C) \[~48\text{ }c{{m}^{2}}\]
D) \[~32\text{ }c{{m}^{2}}\]
Correct Answer: A
Solution :
\[\Delta ABC\]is a right triangle. \[\therefore \]\[A{{C}^{2}}+B{{C}^{2}}=16+9=25\] \[\Rightarrow \]\[AC=5\,cm\] Area of the quad. ABCD = Area of rt. \[\Delta ABC+Area\,of\,rt.\,\Delta ACD\] \[=\frac{1}{2}\times 4\times 3+\frac{1}{2}\times 5\times 12=6+30=36\,c{{m}^{2}}\]
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