A) \[~9\,c{{m}^{2}}\]
B) \[~12\text{ }c{{m}^{2}}\]
C) \[~15\,c{{m}^{2}}\]
D) \[~18\,c{{m}^{2}}\]
Correct Answer: D
Solution :
Draw a parallel line EF to AD and BC Then, area of\[\Delta AOD\] \[=\frac{1}{2}\](area of rectangle AFED) ?(i) Also \[ar(\Delta BOC)=\frac{1}{2}\](rectangle FBCE) ?(ii) Adding (i) & (ii), we get area \[\Delta \Alpha {\mathrm O}D+\]area of\[\Delta \Beta {\mathrm O}C\] \[=\frac{1}{2}(area\,of\,rectangle\,AFED\,+area\,of\,FBCE)\] \[\Rightarrow \]\[(3+6)c{{m}^{2}}=\frac{1}{2}\](area of rectangle ABCD) \[\Rightarrow \]area of rectangle\[ABCD=18\,c{{m}^{2}}\]You need to login to perform this action.
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