A) 17cm
B) 12cm
C) 10cm
D) 15cm
Correct Answer: D
Solution :
We have AD =12 cm, AE = 8 cm and CF = 10 cm Area of parallelogram = \[\text{base }\!\!\times\!\!\text{ height}\] \[\text{=AD}\times \text{CF=12}\times 10=120\,c{{m}^{2}}\] ?(i) Again area of parallelogram \[=CD\times AE\] \[\Rightarrow \]\[120=CD=8\]\[\Rightarrow \]\[CD=15\,cm\]You need to login to perform this action.
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