A) 1
B) 2
C) 3
D) 4
Correct Answer: A
Solution :
We have \[(x+1)+(x+4)+.........+(x+28)=155\] Let \[n\] be the number of terms in the A.P. on L.H.S. Then \[x+28=(x+1)+(n-1)3\]\[\Rightarrow \]\[n=10\] \[\therefore \] \[(x+1)+(x+4)+......+(x+28)=155\] \[\Rightarrow \] \[\frac{10}{2}[(x+1)+(x+28)]=155\]\[\Rightarrow \]\[x=1\].You need to login to perform this action.
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