A) 1
B) 8
C) 4
D) 6
Correct Answer: C
Solution :
Let first 3 terms be \[a-d,a\,\,\]and \[a+d\] Now \[(a-d)+(a+d)=12\] \[\Rightarrow \] \[2a=12\] \[\Rightarrow \] \[a=6\] and \[(a-d)a=24\] Þ \[6(6-d)=24\] Þ \[d=2\] \ First term = \[a-d=6-2=4\].You need to login to perform this action.
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