A) \[x\]
B) \[y\]
C) 0
D) 1
Correct Answer: C
Solution :
Let \[x+y=u,\,\,x-y=v\] Þ \[x=\frac{u+v}{2},y=\frac{u-v}{2}\],\[\therefore f(u,v)=\left( \frac{u+v}{2} \right).\left( \frac{u-v}{2} \right)\] Now,\[\frac{f(x,y)+f(y,x)}{2}=\frac{\left( \frac{x+y}{2}.\frac{x-y}{2} \right)+\left( \frac{y+x}{2}.\frac{y-x}{2} \right)}{2}=0\]You need to login to perform this action.
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