A) 1
B) \[-1\]
C) 0
D) 1/2
Correct Answer: C
Solution :
Suppose that first term and common difference of A.P.'s are \[A\]and D respectively. Now, \[{{p}^{th}}\] term \[=A+(p-1)D=a\] ?..(i) \[{{q}^{th}}\]term \[=A+(q-1)D=b\] ......(ii) and \[{{r}^{th}}\] term \[=A+(r-1)D=c\] ?..(iii) So, \[a(q-r)+b(r-p)+c(p-q)\] \[=a\left\{ \frac{b-c}{D} \right\}+b\left\{ \frac{c-a}{D} \right\}+c\left\{ \frac{a-b}{D} \right\}\] \[=\frac{1}{D}(ab-ac+bc-ab+ca-bc)=0\].You need to login to perform this action.
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