A) 1
B) \[-1\]
C) 0
D) None of these
Correct Answer: C
Solution :
\[\frac{{{a}^{n+1}}+{{b}^{n+1}}}{{{a}^{n}}+{{b}^{n}}}=\frac{a+b}{2}\] \[\Rightarrow \] \[{{a}^{n+1}}-a{{b}^{n}}+{{b}^{n+1}}-b{{a}^{n}}=0\]\[\Rightarrow \]\[(a-b)({{a}^{n}}-{{b}^{n}})=0\] If\[{{a}^{n}}-{{b}^{n}}=0\]. Then\[{{\left( \frac{a}{b} \right)}^{n}}=1={{\left( \frac{a}{b} \right)}^{0}}\]. Hence\[n=0\].You need to login to perform this action.
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