A) 4
B) 8
C) 11
D) 14
Correct Answer: A
Solution :
Suppose that three numbers are \[a+d,\ a,\ a-d,\] therefore \[a+d+a+a-d=33\]\[\Rightarrow \]\[a=11\] \[a(a+d)(a-d)=792\]\[\Rightarrow \]\[11(121-{{d}^{2}})=792\]\[\Rightarrow \]\[d=7\] Then required numbers are 4, 11, 18. Hence smallest number is 4.You need to login to perform this action.
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