A) \[\frac{2}{3}\]
B) \[\frac{3}{2}\]
C) 1
D) \[\frac{3}{4}\]
Correct Answer: C
Solution :
For sequence, x, \[{{a}_{1}},{{a}_{2}},y\] \[y==x+3d\] \[\Rightarrow \] \[d=\frac{y-x}{3}\] \[\Rightarrow \] \[{{a}_{1}}=x+\frac{y-x}{3},{{a}_{2}}=x+2\left[ \frac{y-x}{3} \right]\] and Similarly, \[{{a}_{2}}-{{a}_{1}}=\left[ \frac{y-x}{3} \right]\] For sequence, x, \[{{b}_{1}},{{b}_{2}},y\] \[d'=\frac{y-x}{3}\] and \[{{b}_{2}}-{{b}_{1}}=\frac{y-x}{3}\] \[\Rightarrow \] \[\frac{{{a}_{2}}-{{a}_{1}}}{{{b}_{2}}-{{b}_{1}}}=1\]You need to login to perform this action.
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