A) Rs.156800
B) Rs.156700
C) Rs.165200
D) Rs.166800
Correct Answer: D
Solution :
Amount paid in cash \[=Rs.\left( \frac{1}{2}\times 120000 \right)=Rs.\,\,60000\] Remaining amount \[=\text{ Rs}\text{.(}120000-60000)\text{ =Rs}\text{. }60000\]Amount of 1st instalment \[=Rs.(5000+\frac{12}{100}\times 60000)=Rs.\,12200\] Amount of 2nd instalment \[=Rs.(5000+\frac{12}{100}\times 55000)=Rs.\,11,600\] Amount of 3rd instalment \[=Rs.\,\left( 5000+\frac{12}{100}\times 50000 \right)=Rs.\,11,000\] Total amount paid \[=Rs.12200+Rs.11600+Rs.11000\]+... (12 instalments) which form an A.P. with number of terms, \[n=12,\text{ }a=12200\]and \[d=-600\] \[\therefore \] Sum \[=n\frac{n}{2}\left[ 2a+(n-1)d \right]\] \[=\frac{12}{2}\left[ 2\times 12200+11\times \left( -600 \right) \right]=106800\] \[\therefore \] Total cost of the shop \[=Rs.60000+Rs.106800=Rs.166800\]You need to login to perform this action.
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