A) \[{{n}^{2}}+10n\]
B) \[{{n}^{2}}-10n\]
C) \[10n-{{n}^{2}}\]
D) \[{{n}^{2}}\]
Correct Answer: A
Solution :
Odd numbers starting from 11 are 11, 13, 15, 17, 19, .... Sum to 'n' odd numbers, where a = 11, d = 2 is \[p(-1)={{(-1)}^{2}}+3(-1)-2=(-4)\]\[p(-1)=-4\]You need to login to perform this action.
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