A) \[p+q-n\]
B) \[p+q+n\]
C) \[p-q+n\]
D) \[p-q-n\]
Correct Answer: A
Solution :
We have given that \[{{a}_{p}}=q\] and \[{{a}_{q}}=p\] \[\Rightarrow \] \[q=a+(p-1)d\] and ... (i) \[p=a+(q-1)d\] ... (ii) Subtracting (ii) from (i), we get \[q-p=d(p-q)\Rightarrow d=-1\] Now, \[q=a+1-p\] [From (i)]; \[\Rightarrow \] \[a=q+p-1\] \[\therefore \] \[{{a}_{n}}=a+(n-1)d=q+p-1+(n-1)(-1)\] \[=q+p-1+1-n=q+p-n\]You need to login to perform this action.
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