A) 40500
B) 20000
C) 20500
D) 31500
Correct Answer: D
Solution :
Since, production of TV in 6th year = 8000 \[\Rightarrow \] \[{{a}_{6}}=8000\Rightarrow a+5d=8000\] ....(i) Also, production of TV in 9th year = 11300 \[\Rightarrow \] \[{{a}_{9}}=11300\]or\[a+8d=11300\] ....(ii) Subtracting (i) from (ii), we get \[3d=3300\,\,\Rightarrow \,d=1100\] From (i), a = 2500 \[\therefore \] Production in 6 years, i.e., \[{{S}_{6}}=\frac{6}{2}\left[ 2\left( 2500 \right)+\left( 6-1 \right)\left( 1100 \right) \right]=31500\]
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