A) 3
B) \[\frac{1}{3}\]
C) \[\frac{1}{9}\]
D) 9
Correct Answer: A
Solution :
Given \[{{3}^{n}}=27={{3}^{3}}\] \[\therefore \] \[n=3\] Thus \[{{3}^{n-2}}={{3}^{3-2}}={{3}^{1}}=3\]
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