8th Class Mathematics Related to Competitive Exam Question Bank Arithmetic

  • question_answer
    The average of twenty results is 18, that of first 9 is Hand that of last 9 is 17. The average of middle two results is

    A) 45                         

    B) 50.5

    C) 40.5             

    D) 51.5

    Correct Answer: C

    Solution :

    Let \[=\frac{9}{45}hr=\frac{1}{5}\times 60=12\min .\] be the twenty results. \[\frac{{{a}_{1}}+{{a}_{2}}+...+{{a}_{9}}+{{a}_{10}}+{{a}_{11}}+{{a}_{12}}+...{{a}_{20}}}{20}=18\]      ?(1) Also  \[20\times 2.40=Rs.48\]\[400\times \frac{110}{100}\times \frac{110}{100}=484\]\[1000\times \frac{(100-30)}{100}\times \frac{(100-40)}{100}\] And \[\frac{{{a}_{12}}+...+{{a}_{20}}}{9}=17\]\[\because \]\[\frac{25}{100}\times x=20,000\] Put in equation (1), we get \[126+153+{{a}_{10}}+{{a}_{11}}=20\times 18\]\[=\frac{40}{100}\times 80,000=32,000.\]\[{{a}_{10}}+{{a}_{11}}=81\] \[=\frac{35}{36}\times 100=97\frac{2}{3}%\approx 97%\]Average of \[=\frac{(100-5)}{100}\times \frac{(100-10)}{100}\times original=171\] and \[\therefore \]     


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