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9th Class Mathematics Related to Competitive Exam Question Bank Arithmetic

  • question_answer
    The divisor when the quotient, divident and the remainder are respectively 547, 171282 and 71 is equal to

    A)  333                       

    B)         323

    C)  313                         

    D)         303

    Correct Answer: C

    Solution :

     Let \[x\] be the required divisor, then                 \[x\times 547+71=171282\] or            \[x\times 547=171282=171211\] \[\therefore \]  \[x=\frac{171211}{547}=313\]


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