A) 700
B) 740
C) 750
D) 780
Correct Answer: C
Solution :
Let C.P. of first watch = Rs.x So C.P. of second watch \[\left. \begin{matrix} \frac{48}{5}:9 \\ 5:8 \\ \end{matrix} \right\}::900:x\] Now, S.P. of first watch \[x=900\times \frac{9}{48/5}\times \frac{8}{5}=1350lit.\] Now, S.P. of second watch \[=\frac{1}{20}\times 3+\frac{1}{30}\times 1+\frac{1}{60}\times 1=\frac{1}{5}\] According to question, \[\therefore \] \[=3\times 5=15\] \[P=\frac{1}{25};Q=\frac{1}{30}\]
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