A) - 1
B) 0
C) 1
D) \[abc\]
Correct Answer: C
Solution :
Consider\[{{a}^{1}}={{b}^{x}}={{({{c}^{y}})}^{x}}\] \[={{[{{({{a}^{2}})}^{y}}]}^{x}}={{a}^{zyx}}\] \[\therefore \] \[1=xyz\] or \[xyz=1\]
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