question_answer

If \[p={{x}^{\frac{1}{3}}}+{{x}^{\frac{1}{3}}}\] , then \[{{p}^{3}}-3p\] is equal to

A)  3                            

B)         \[\frac{1}{2}(x+{{x}^{-1}})\]

C)  \[x+{{x}^{-1}}\]               

D)         \[2(x+{{x}^{-1}})\]