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9th Class Mathematics Related to Competitive Exam Question Bank Arithmetic

  • question_answer
    If \[\frac{100\sqrt{25}}{\sqrt{25}+x}=50\], then the value of \[x\] is

    A)  25                         

    B)         \[\frac{1}{\sqrt{25}}\]  

    C)  \[\sqrt{25}\]                       

    D)  \[\frac{1}{25}\]

    Correct Answer: C

    Solution :

                    \[\frac{100\sqrt{25}}{\sqrt{25}+x}=50\] or            \[\frac{100\times 5}{5+x}=50\] or            \[500=250+50x\] or            \[50x=250\] \[\therefore \]  \[x=\frac{250}{50}\]                    \[=5=\sqrt{25}\]


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