A) \[\sqrt{3}+1\]
B) \[\sqrt{2}-1\]
C) \[\sqrt{2}-2\]
D) \[\sqrt{2}+2\]
Correct Answer: D
Solution :
Given\[\sqrt{3}:(1+\sqrt{2}):\,\,:\sqrt{6}:x\] \[\Rightarrow \] \[\frac{\sqrt{3}}{1+\sqrt{2}}=\frac{\sqrt{6}}{x}\] \[\therefore \] \[x=\frac{\sqrt{6}\cdot (1+\sqrt{2})}{\sqrt{3}}=\frac{\sqrt{2}.\sqrt{3}(1+\sqrt{2})}{\sqrt{3}}\] \[=\sqrt{2}(1+\sqrt{2})=\sqrt{2}+\sqrt{2}.\sqrt{2}\] \[=\sqrt{2}+2\]
You need to login to perform this action.
You will be redirected in
3 sec
