A) \[\frac{1}{7}\]
B) \[\frac{1}{2}\]
C) 1
D) 2
Correct Answer: D
Solution :
Given that \[\frac{a}{3}=\frac{b}{4}=\frac{c}{7}\] We can assume a constant\[k\], such that \[\frac{3k+4k+7k}{7k}=\frac{14k}{7k}=2\] \[\frac{a+b+c}{c}=2\]
You need to login to perform this action.
You will be redirected in
3 sec
