A) 100 km
B) 200 km
C) 300 km
D) 400 km
Correct Answer: B
Solution :
Let \[t\] hrs. be the time taken by the car \[B\] to reach the crossing point. Hence, \[A\] will take \[(t+1)\] hrs. to reach the same point. Speed of car\[B=50\,\,km/hr\]. Distance covered before the crossing\[=50\times t\] Now, using the strategy (4), we know that the total distance covered by the two cars is the total distance between their starting points. \[i.e.\] \[40(t+1)+50t=400\] \[\Rightarrow \] \[40t+50t+40=400\] \[\Rightarrow \] \[90t=360\] \[\Rightarrow \] \[t=4\,\,hrs.\] Hence, the distance covered by car \[B=50\times 4=200\,\,km\].You need to login to perform this action.
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