A) 40min
B) 32min
C) 28min
D) 48min
Correct Answer: C
Solution :
Let usual rate be .x km/min and distance be y km then time is \[\frac{4}{12}=\frac{7}{21}=\frac{21}{63}=\frac{28}{84}=\frac{1}{3}.\] min as per question. \[\frac{1}{3}\] \[\frac{1}{3}\] \[{{b}_{1}},{{b}_{2}}\] \[{{a}_{1}},{{a}_{2}}\] \[{{a}_{1}}\,\,{{b}_{1}}\] \[\frac{y}{x}=28\] (min)You need to login to perform this action.
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