A) 8. 30 a.m.
B) 9 a.m.
C) 9. 30 a.m.
D) 10 am
Correct Answer: C
Solution :
Let \[t\] be the time taken for the scooter to travel the distance, so as to overtake the bicycle. The time taken by the bicycle to cover the same distance will be\[(t+1)\]. The speed of the bicycle is \[10\,\,km/hr\] and that of the scooter is\[30\,\,km/hr\]. Now, using the strategy, the distance travelled by the scooter as well as the bicycle till the point of overtake will be the same. \[i.e.\] \[30\times t=10\times (t+1)\] \[\Rightarrow \] \[30t=10t+10\] \[\Rightarrow \] \[30t-10t=10\] \[\Rightarrow \] \[20t=10\] \[\Rightarrow \] \[t=\frac{1}{2}hour\] \[=30\,\,mins\] Hence, the scooter will overtake the bicycle at \[9:30\,\,a.m.\]
You need to login to perform this action.
You will be redirected in
3 sec
