A) \[C{{H}_{3}}Cl\]/anhy.\[AlC{{l}_{3}}\]
B) \[C{{l}_{2}}\]/sunlight
C) \[{{C}_{2}}{{H}_{5}}I\]/anhy.\[AlC{{l}_{3}}\]
D) \[C{{H}_{3}}COCl/AlC{{l}_{3}}\]
Correct Answer: B
Solution :
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