A) 25 gm
B) 2.5 gm
C) 60 gm
D) 40 gm
Correct Answer: A
Solution :
\[n=\frac{40}{20}=2\] \[\therefore \] Amount left \[\frac{{{N}_{0}}}{{{2}^{n}}}=\frac{100}{{{2}^{2}}}=25gm\]You need to login to perform this action.
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