12th Class Mathematics Inverse Trigonometric Functions Question Bank Assertion And Reason (MCQs) - Inverse Trigonometric Functions

  • question_answer
    Assertion [A]: The principal value of \[{{\cos }^{-1}}\left( \cos \frac{13\pi }{6} \right)\]is \[\frac{\pi }{6}\].
    Reason [R]: The principal value of \[{{\tan }^{-1}}\left( \tan \,\frac{5\pi }{6} \right)\] is \[\frac{5\pi }{6}\].

    A) Both A and R are individually true and R is the correct explanation of A.

    B) Both A and R are individually true and R is not the correct explanation of A.

    C) 'A' is true but 'R' is false

    D) 'A' is false but 'R' is true

    E) Both A and R are false.

    Correct Answer: C

    Solution :

    \[{{\cos }^{-1}}\left( \cos \frac{13\pi }{6} \right)={{\cos }^{-1}}\left( \cos \left( 2\pi +\frac{\pi }{6} \right) \right)\] \[={{\cos }^{-1}}\left( \cos \frac{\pi }{6} \right)=\frac{\pi }{6}\]. Reason (R) : \[{{\tan }^{-1}}\left( \tan \frac{5\pi }{6} \right)={{\tan }^{-1}}\left( \tan \left( \pi -\frac{\pi }{6} \right) \right)\] \[={{\tan }^{-1}}\left( -\tan \frac{\pi }{6} \right)=-\frac{\pi }{6}\]. Here Assertion [A] is true and Reason [R] is false. \[\therefore \]Option [C] is the correct answer.


You need to login to perform this action.
You will be redirected in 3 sec spinner