10th Class Mathematics Polynomials Question Bank Assertion and Reason MCQs - Polynomials

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    Directions: Each of these questions contains two statements: Assertion [A] and Reason [R]. Each of these questions also has four alternative choices, any one of which is the correct answer. You have to select one of the codes [a], [b], [c] and [d] given below.
    Assertion [A] If \[{{x}^{2}}+x-12\] divides \[{{x}^{2}}+x-12\] exactly, then \[a=-8\] and b = - 5
    Reason [R] When a polynomial \[p\left( x \right)\]is completely divided by \[\left( x-\alpha  \right)\], then \[p\left( x \right)=0\].
     

    A) A is true, R is true; R is a correct explanation for A.

    B) A is true, R is true; R is not a correct explanation for A.

    C) A is true; R is False.

    D) A is false; R is true.

    Correct Answer: D

    Solution :

    Let  \[f\left( x \right)={{x}^{2}}+x-12\]
     \[={{x}^{2}}+4x-3x-12\]
     \[=x\left( x+4 \right)-3\left( x+4 \right)\]
     \[=\left( x-3 \right)\left( x+4 \right)\]
     \[p\left( 3 \right)=0=p\left( -4 \right)\]
     \[p\left( 3 \right)={{3}^{3}}+a{{\left( 3 \right)}^{2}}+b\left( 3 \right)-84=0\]
     \[27+9a+3b-84=0\]
     \[9a+3b=57\]                                      …. (i)
    \[p\left( -4 \right)={{\left( -4 \right)}^{3}}+a{{\left( -4 \right)}^{2}}+b\left( -4 \right)-84=0\]
    \[\Rightarrow \,\,-64+16a-4b-84=0\]
    \[4a-b=37\]
    \[12a-3b=111\]                                      .… (ii)
    Adding Eqs. (i) and (ii)                                              
    \[21a=168\]
    \[a=8\]
     Substitute a = 8 in Eq. (i)
    \[9\times 8+3\times b=57\]
    \[72\text{ }+\text{ }3b\text{ }=\text{ }57\]
    \[3b=-15\]
     \[b=-5\]
     Hence, Assertion is false but Reason is true.
     


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