| Assertion (A): In a simultaneously throw of a pair of dice. The probability of getting a double is \[\frac{1}{6}\]. |
| Reason (R): Probability of an event may be negative. |
A) Both assertion (A) and reason (R) are true and reason (R) is the correct explanation of assertion (A).
B) Both assertion (A) and reason (R) are true but reason (R) is not the correct explanation of assertion (A)
C) Assertion (A) is true but reason (R) is false.
D) Assertion (A) is false but reason (R) is true.
Correct Answer: C
Solution :
| [c] Assertion (A) is true but reason (R) is false. When two dice are tossed. Total possible outcomes =36 |
| \[n(S)=36\] and total favorable outcomes (doublet) |
| \[=\{(1,1),(2,2),(3,3),(4,4),(5,5),(6,6)\}\] |
| \[n(E)=6\] |
| Probability \[=\frac{6}{36}=\frac{1}{6}\]and, we know that \[0\le P(E)\le 1.\] |
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